Hi Prateek,
You can use the Virtuoso SPARQL transitivity option with SKOS to obtain
hierarchy trees for resource as detail in the follow tutorial example:
http://virtuoso.openlinksw.com/presentations/SPARQL_Tutorials/SPARQL_Tutorials_Part_2/SPARQL_Tutorials_Part_2.html#(34)
Additonal documentation on Virtuoso SPARQL transitivity option and use with
SKOS can be obtained from:
http://docs.openlinksw.com/virtuoso/rdfsparqlrule.html#rdfsparqlruletransoption
http://docs.openlinksw.com/virtuoso/rdfsparql.html#rdfsparqlimplementatiotrans
Best Regards
Hugh Williams
Professional Services
OpenLink Software
Web: http://www.openlinksw.com
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On 8 Apr 2010, at 18:08, Prateek wrote:
> Hello,
> I am trying to obtain the entire hierarchy tree for any given
> resource.
>
> To give an example
>
> If the resource is http://dbpedia.org/page/India
>
> For this obtain
>
> category:Liberal_democracies
> category:Members_of_the_Commonwealth_of_Nations
> category:States_and_territories_established_in_1947
> category:Former_British_colonies
> category:G15_nations
> category:G20_nations
> category:India
> category:South_Asia
> category:South_Asian_Association_for_Regional_Cooperation_member_states
> category:Federal_countries
> category:Countries_of_the_Indian_Ocean
> category:English-speaking_countries_and_territories
> category:Republics
> category:South_Asian_countries
>
>
> Then for each category in which the resource falls, obtaining the parent
> category of those
> lets say category:Liberal_democracies and getting
>
> category:Liberalism
> category:Countries_by_form_of_government
> category:Democracy
>
>
> and so on...
>
> Any suggestions as to how I can do this using a SPARQL query or web service?
>
> Thanks,
>
> Prateek
> --
> Prateek Jain
> PhD Student, Research Assistant
> Web: http://prateek-jain.com
> Email: [email protected]
> Phone: (770) 406-6356
> <prateek.vcf>------------------------------------------------------------------------------
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