On 10/06/2017 07:20 AM, 'Maxi Miller' via deal.II User Group wrote:
Isn't that basically the method done in step-15 and step-33 (line search)? But
why should my step length (I assume it is alpha) go to zero? Or is it the
newton-update (which also should go to zero, when being close to the solution)?
The step length is alpha in
u_{n+1} = u_n + alpha delta u_n
I don't think step-15 uses a line search (i.e., it *always* uses alpha=1). I
don't recall about step-33.
Your question "why should my step length (I assume it is alpha) go to zero?"
Is the wrong one. Maybe it shouldn't. The question is whether it does.
Debugging is all about understanding that what you *think is true* is
apparently not true. So you have to test hypotheses.
Best
W.
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Wolfgang Bangerth email: [email protected]
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