Dear all, Sorry for the spam - a basic mathematical question.
In the step-3 example (https://www.dealii.org/8.4.1/doxygen/deal.II/step_3.html), I noticed that at first the variable phi is used as a test function. It is in the same space with u, except for that the value is 0 on the boundaries. (in this problem the boundary values for u is also 0, but it could be non-zero for general cases) However, later, the variable phi is also the shape function. I am lost in this step in understanding why the test function could be the shape function at the same time. For example, if the boundary conditions of u is non-zero, we'd have to have a shape function to be non-zero at the boundary (right?) but the test function space needs to be 0 on the boundary. Could you please help? Thank you, Shawn -- The deal.II project is located at http://www.dealii.org/ For mailing list/forum options, see https://groups.google.com/d/forum/dealii?hl=en --- You received this message because you are subscribed to the Google Groups "deal.II User Group" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
