Georgios,

Thanks for your reply! Essentially what I was trying to do is patch together two product spaces:  ([H1_0]^2, L^2_0) in one part of the domain and ([H1_0]^2, L^2_0) in another, with an interface condition to ensure solvability for my problem (Stokes in one part of the domain, laplace in another).  The interface condition was chosen such that there would be no jump of the velocity gradient across the interface (this was done by choosing an L2_0 pressure that goes in the right-hand side).

Can you state this interface condition in mathematical terms? In general, functions in H^1 can be expected to be continuous along interfaces, but their gradients can not. Indeed, their normal derivatives along the interface will only be in H^{-1/2}, and so the difference between the normal derivatives from both sides of the interface can at best be expected to be weakly continuous (i.e., when tested with a sufficiently smooth test function).


   Unfortunately this did not work in the implementation phase and I ended up getting a jump of the velocity gradient across the interface.

But is this different than the jump in the gradient between each cell and the next? There, the gradient is not continuous either. The question is what happens as you let the mesh size go to zero.


  At the moment I don't know if this is a coding bug, or an erroneous choice of spaces.  To be honest I expected weak differentiability to be enough to ensure a zero velocity gradient jump across the interface too. As such, I was thinking how I should choose my spaces to ensure gradient continuity across the interface to see if this would fix my problem but I do not know how to enforce that in deal.ii.  As such, any advice on how to do that would be great.

It's actually quite complicated to ensure continuity of the gradient strongly. This is why the biharmonic equation is so difficult to solve!

Best
 Wolfgang

--
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Wolfgang Bangerth          email:                 [email protected]
                           www: http://www.math.colostate.edu/~bangerth/

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