On 12/9/18 11:42 AM, Jaman wrote:
>
> for (; cell!=endc; ++cell)
> {
> fe_values.reinit(cell);
>
> fe_values[velocities].get_function_gradients(old_timestep_solution,
> old_time_gradient_values);
>
> }
Yes, this works.
> My question is: I need to compute the transpose of the gradient values '(grad
> u^{n-1})^T' at the quadrature points. How can I do it? Please help me. I
> appreciate your help.
It's as simple as using
transpose(old_time_gradient_values[q_point])
in the expression where you need the transpose of the gradient.
Best
W.
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Wolfgang Bangerth email: bange...@colostate.edu
www: http://www.math.colostate.edu/~bangerth/
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