I tried to follow the examples for setting up a LinearOperator (such as 
shown in Step-22 and Step-20), but instead of a matrix I wanted to provide 
my own function which should serve as vmult-function (i.e. a matrix-free 
linear operator). Is that possible? My initial test was the following code:

  class approximator : public Subscriptor 
    { 
    public: 
       approximator(std::function<void(const Vector<double>&, 
                                                    Vector<double>&)> 
residual_function, 
                            const Vector<double> &evaluation_point) : 
            residual_function(residual_function)
        { 
            u = evaluation_point; 
            u.add(1); 
            epsilon_val = u.l1_norm() * 1e-6; 
            residual_function(u, residual_0); 
        }; 
    
        void vmult(Vector<double> &dst, const Vector<double> &src) const; 
    
    private: 
        std::function<void(const Vector<double>&, 
                           Vector<double>&)> residual_function; 
        double epsilon_val; 
        Vector<double> u, residual_0, residual_1; 
    };


const auto op_M = linear_operator(jacobian_approximation(std::bind(&
MinimalSurfaceProblem<dim>::compute_residual,
                                                                       this,
                                                                       std::
placeholders::_1,
                                                                       std::
placeholders::_2), 
                                                            
 present_solution));

but that resulted in
error: use of deleted function ‘dealii::LinearOperator<Range, Domain, 
Payload> dealii::linear_operator(Matrix&&) [with Range = dealii::Vector
<double>; Domain = dealii::Vector<double>; Payload = dealii::internal::
LinearOperatorImplementation::EmptyPayload; Matrix = Step15::
jacobian_approximation; <template-parameter-1-5> = void]’
  389 |                                                             
 present_solution));
Are there other ways?
Thanks!


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