On 10/21/20 7:46 PM, Doug Shi-Dong wrote:
Thanks, yes, that should work well for 2D. I actually just thought of a corner case (pun intended) in 3D. It is possible for a cell's vertex to be on a boundary, without any of its neighbour actually have a boundary face.

Yes, precisely: None of the face neighbors have to be on the boundary. But at least one of the vertex neighbors have to be -- which is why the ghost layer consists of all of the vertex neighbors of locally owned cells.

You can create the same situation in 2d, by the way: Start with a single vertex and put 5 or more quadrilateral cells around it. Then put another layer of cells around those. Then remove one of the cells that are adjacent to the original vertex and look at the cell opposite from it.


Any advice on how to approach this since the current processor would not find it within its ghost cells?

Yes, it will -- see above.
W.

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Wolfgang Bangerth          email:                 [email protected]
                           www: http://www.math.colostate.edu/~bangerth/

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