[image: grafik.png]
[image: grafik.png]
The only place I use Dev_P is to compute the above double contractions ('P'
in the above is what dealii returns as Dev_P)
As you can see, the fourth order tangent C_bar consists of outer products
of second order symmetric tensors:
boldsymbol 'I' is the second order unit tensor, C_bar is a symmetric second
order tensor, and blackboard 'I' is the general fourth order unit tensor,
the deltas are just scalars.

In my opinion, the double contractions 'P : outer_product(C_bar, C_bar)'
and 'P : I' produce different results if the fourth order symmetric unit
tensor 'S' is used to define 'P' .
The same holds also for doing the double contractions with P_T.
Correct?

Best
Simon

Am Mo., 8. Aug. 2022 um 12:54 Uhr schrieb Wolfgang Bangerth <
[email protected]>:

> On 8/7/22 06:00, Simon wrote:
> >
> > the fourth-order referential deviatoric tensor as returned by
> > Physics::Elasticity::StandardTensors
> > <
> https://nam10.safelinks.protection.outlook.com/?url=https%3A%2F%2Fwww.dealii.org%2Fcurrent%2Fdoxygen%2Fdeal.II%2FclassPhysics_1_1Elasticity_1_1StandardTensors.html&data=05%7C01%7CWolfgang.Bangerth%40colostate.edu%7Cc7d0b41aa97a4f5bbf6a08da786c79b6%7Cafb58802ff7a4bb1ab21367ff2ecfc8b%7C0%7C0%7C637954704552090273%7CUnknown%7CTWFpbGZsb3d8eyJWIjoiMC4wLjAwMDAiLCJQIjoiV2luMzIiLCJBTiI6Ik1haWwiLCJXVCI6Mn0%3D%7C3000%7C%7C%7C&sdata=u9Z1RfLeZdT2vdeD7%2BNYIXWA8h%2Bkvtdre4KIewAI0ws%3D&reserved=0><
>
> > dim >::Dev_P
> > includes the fourth-order referential/spatial unit *symmetric* tensor
> > Physics::Elasticity::StandardTensors
> > <
> https://nam10.safelinks.protection.outlook.com/?url=https%3A%2F%2Fwww.dealii.org%2Fcurrent%2Fdoxygen%2Fdeal.II%2FclassPhysics_1_1Elasticity_1_1StandardTensors.html&data=05%7C01%7CWolfgang.Bangerth%40colostate.edu%7Cc7d0b41aa97a4f5bbf6a08da786c79b6%7Cafb58802ff7a4bb1ab21367ff2ecfc8b%7C0%7C0%7C637954704552090273%7CUnknown%7CTWFpbGZsb3d8eyJWIjoiMC4wLjAwMDAiLCJQIjoiV2luMzIiLCJBTiI6Ik1haWwiLCJXVCI6Mn0%3D%7C3000%7C%7C%7C&sdata=u9Z1RfLeZdT2vdeD7%2BNYIXWA8h%2Bkvtdre4KIewAI0ws%3D&reserved=0><
>
> > dim >::S = identity_tensor
> > <
> https://nam10.safelinks.protection.outlook.com/?url=https%3A%2F%2Fwww.dealii.org%2Fcurrent%2Fdoxygen%2Fdeal.II%2Fsymmetric__tensor_8h.html%23ab3e890348aa219805e84f7d367e098c3&data=05%7C01%7CWolfgang.Bangerth%40colostate.edu%7Cc7d0b41aa97a4f5bbf6a08da786c79b6%7Cafb58802ff7a4bb1ab21367ff2ecfc8b%7C0%7C0%7C637954704552090273%7CUnknown%7CTWFpbGZsb3d8eyJWIjoiMC4wLjAwMDAiLCJQIjoiV2luMzIiLCJBTiI6Ik1haWwiLCJXVCI6Mn0%3D%7C3000%7C%7C%7C&sdata=3bQQR2Em7YyxuQuohp19IsBWntxKehAhRzin%2F0GFlBs%3D&reserved=0
> ><dim>().
> >
> > In the literature, for instance G. A. Holzapfel: "Nonlinear solid
> mechanics. A
> > Continuum Approach for Engineering" (2007),
> > however, the general fourth-order unit tensor
> > I_{ijkl} = delta_{ik} delta_{jl} is used to compute Dev_P.
> >
> > I implemented a hyperelastic material model with a volumetric /
> isochoric
> > split of the strain energy function and it only converges when using 'S'
> - as
> > dealii does it. Using the  general fourth-order unit tensor to define
> Dev_P,
> > my solver does not converge at all.
> >
> > Is it neccessary to use 'S' due to the way dealii stores and accesses
> the
> > elements of symmetric tensors?
>
> The question is what you apply I or S to. If you apply them to symmetric
> rank-2 tensors, then they are the same. If you apply them to non-symmetric
> tensors, then they are not.
>
> Best
>   W.
>
>
> --
> ------------------------------------------------------------------------
> Wolfgang Bangerth          email:                 [email protected]
>                             www: http://www.math.colostate.edu/~bangerth/
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