Your message dated Sun, 18 Nov 2018 17:13:25 +0000
with message-id <[email protected]>
and subject line Bug#910954: Removed package(s) from unstable
has caused the Debian Bug report #533042,
regarding tomboy-latex: Becomes incredibly slow with larger notes
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533042: https://bugs.debian.org/cgi-bin/bugreport.cgi?bug=533042
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--- Begin Message ---
Package: tomboy-latex
Version: 0.5-1
Severity: normal
Hi!
With larger notes tomboy (with LaTeX-plugin enabled) becomes really slow. I
can often type whole sentences without any feedback from tomboy (no cursor
movement, no charachters appearing, and tomboys windows don't redraw if I drag
another window over it). When I'm finished typing and wait for about 30-60
seconds, the typed stuff will appear all at once. My impression is that there
is some O(n^2) behaviour there, where n is either the total size of the note
or the number of equations in it.
A sample note is attached.
Thanks,
Jö.
-- System Information:
Debian Release: squeeze/sid
APT prefers testing-proposed-updates
APT policy: (500, 'testing-proposed-updates'), (500, 'testing')
Architecture: i386 (i686)
Kernel: Linux 2.6.28-1-686-bigmem (SMP w/2 CPU cores)
Locale: LANG=de_DE.UTF-8, LC_CTYPE=de_DE.UTF-8 (charmap=UTF-8)
Shell: /bin/sh linked to /bin/bash
Versions of packages tomboy-latex depends on:
ii imagemagick 7:6.4.5.4.dfsg1-1 image manipulation programs
ii libgtk2.0-cil 2.12.8-2 CLI binding for the GTK+ toolkit 2
ii libmono-corlib2.0-cil 2.0.1-6 Mono core library (for CLI 2.0)
ii libmono-system2.0-cil 2.0.1-6 Mono System libraries (for CLI 2.0
ii texlive-base-bin 2007.dfsg.2-6 TeX Live: Essential binaries
ii texlive-latex-base 2007.dfsg.2-4 TeX Live: Basic LaTeX packages
ii tomboy 0.14.2-1 desktop note taking program using
tomboy-latex recommends no packages.
tomboy-latex suggests no packages.
-- no debconf information
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<?xml version="1.0" encoding="utf-8"?>
<note version="0.3" xmlns:link="http://beatniksoftware.com/tomboy/link";
xmlns:size="http://beatniksoftware.com/tomboy/size";
xmlns="http://beatniksoftware.com/tomboy";>
<title>Edge Basis and Transformation</title>
<text xml:space="preserve"><note-content version="0.1">Edge Basis and
Transformation
<size:huge>The Basis</size:huge>
For the edge basis we have the following properties, which fully determine them:
<list><list-item dir="ltr">Each shape function \[\psi_i\] is linear.
</list-item><list-item dir="ltr">Each shape function maps from \[\mathbb R^n\]
to \[\mathbb R^n\], where \[n\] is the dimension.
</list-item><list-item dir="ltr">For each shape function holds \[\psi_i(\mathbf
x)\cdot\mathbf t^j=\delta_{ij}\quad\forall\mathbf x\in\Gamma^j\], where
\[\Gamma^j\] denotes edge \[j\] and \[\mathbf t^j\] denotes a tangential unit
vector to that edge.</list-item></list>
We use the following numbering of edges and vertices:
<monospace>| edge # | vertex 0 # | vertex 1 # |
| 0 | 0 | 1 |
| 1 | 0 | 2 |
| 2 | 1 | 2 |</monospace>
From that follow the following definitions for the tangential unit vectors
\[\mathbf t^i\] and edge lengthes \[\ell^i\], where \[x^i\] are the coordinates
of vertex \[i\]:
<list><list-item dir="ltr">\[\mathbf t^0=(\mathbf x^1-\mathbf x^0)/\ell^0\],
\[\ell^0=||\mathbf x^1-\mathbf x^0||\]
</list-item><list-item dir="ltr">\[\mathbf t^1=(\mathbf x^2-\mathbf
x^0)/\ell^1\], \[\ell^1=||\mathbf x^2-\mathbf x^0||\]
</list-item><list-item dir="ltr">\[\mathbf t^2=(\mathbf x^2-\mathbf
x^1)/\ell^2\], \[\ell^2=||\mathbf x^2-\mathbf x^1||\]</list-item></list>
Since the shape functions are linear, we write them in the following way:
<list><list-item dir="ltr">\[\psi^i(\mathbf x)=\mathrm A^i\mathbf x+\mathbf
a^i\]</list-item></list>
Evaluating the shape functions at the three vertices and taking the scalar
product with the two adjacent tangential vectors \[\psi^i(\mathbf
x^k)\cdot\mathbf t^j=\delta_{ij}\quad\forall k\in\{j_0,j_1\}\] leaves us with
the following six conditions:
<list><list-item dir="ltr">\[\psi^i(\mathbf x^0)\cdot\mathbf
t^0=\delta_{i0}\quad\Longrightarrow\quad(\mathrm A^i\mathbf x^0+\mathbf
a^i)\cdot(\mathbf x^1-\mathbf x^0)=\delta_{i0}\ell^0\]
</list-item><list-item dir="ltr">\[\psi^i(\mathbf x^1)\cdot\mathbf
t^0=\delta_{i0}\quad\Longrightarrow\quad(\mathrm A^i\mathbf x^1+\mathbf
a^i)\cdot(\mathbf x^1-\mathbf x^0)=\delta_{i0}\ell^0\]
</list-item><list-item dir="ltr">\[\psi^i(\mathbf x^1)\cdot\mathbf
t^2=\delta_{i2}\quad\Longrightarrow\quad(\mathrm A^i\mathbf x^1+\mathbf
a^i)\cdot(\mathbf x^2-\mathbf x^1)=\delta_{i2}\ell^2\]
</list-item><list-item dir="ltr">\[\psi^i(\mathbf x^2)\cdot\mathbf
t^2=\delta_{i2}\quad\Longrightarrow\quad(\mathrm A^i\mathbf x^2+\mathbf
a^i)\cdot(\mathbf x^2-\mathbf x^1)=\delta_{i2}\ell^2\]
</list-item><list-item dir="ltr">\[\psi^i(\mathbf x^2)\cdot\mathbf
t^1=\delta_{i1}\quad\Longrightarrow\quad(\mathrm A^i\mathbf x^2+\mathbf
a^i)\cdot(\mathbf x^2-\mathbf x^0)=\delta_{i1}\ell^1\]
</list-item><list-item dir="ltr">\[\psi^i(\mathbf x^0)\cdot\mathbf
t^1=\delta_{i1}\quad\Longrightarrow\quad(\mathrm A^i\mathbf x^0+\mathbf
a^i)\cdot(\mathbf x^2-\mathbf x^0)=\delta_{i1}\ell1\]</list-item></list>
By pairwise combination we can transform these conditions into
<list><list-item dir="ltr">\[[\mathrm A^i(\mathbf x^1-\mathbf
x^0)]\cdot(\mathbf x^1-\mathbf x^0)=0\quad\Longleftrightarrow\quad(\mathrm
A^i\mathbf t^0)\cdot\mathbf t^0=0\]
</list-item><list-item dir="ltr">\[[\mathrm A^i(\mathbf x^2-\mathbf
x^0)]\cdot(\mathbf x^2-\mathbf x^0)=0\quad\Longleftrightarrow\quad(\mathrm
A^i\mathbf t^1)\cdot\mathbf t^1=0\]
</list-item><list-item dir="ltr">\[[\mathrm A^i(\mathbf x^2-\mathbf
x^1)]\cdot(\mathbf x^2-\mathbf x^1)=0\quad\Longleftrightarrow\quad(\mathrm
A^i\mathbf t^2)\cdot\mathbf t^2=0\]</list-item></list>
and
<list><list-item dir="ltr">\[(\mathrm A^i\mathbf x^0+\mathbf a^i)\cdot(\mathbf
x^2-\mathbf
x^1)=\delta_{i1}\ell^1-\delta_{i0}\ell^0\quad\Longleftrightarrow\quad(\mathrm
A^i\mathbf x^0+\mathbf a^i)\cdot\mathbf
t^2=(\delta_{i1}\ell^1-\delta_{i0}\ell^0)/\ell^2\]
</list-item><list-item dir="ltr">\[(\mathrm A^i\mathbf x^1+\mathbf
a^i)\cdot(\mathbf x^2-\mathbf
x^0)=\delta_{i2}\ell^2+\delta_{i0}\ell^0\quad\Longleftrightarrow\quad(\mathrm
A^i\mathbf x^1+\mathbf a^i)\cdot\mathbf
t^1=(\delta_{i2}\ell^2+\delta_{i0}\ell^0)/\ell^1\]
</list-item><list-item dir="ltr">\[(\mathrm A^i\mathbf x^2+\mathbf
a^i)\cdot(\mathbf x^1-\mathbf
x^0)=\delta_{i1}\ell^1-\delta_{i2}\ell^2\quad\Longleftrightarrow\quad(\mathrm
A^i\mathbf x^2+\mathbf a^i)\cdot\mathbf
t^0=(\delta_{i1}\ell^1-\delta_{i2}\ell^2)/\ell^0\]</list-item></list>
Mayhaps these will be useful later.
<size:huge>Coordinate Transformation
</size:huge>
For transformation we use a mapping \[\mathbf x=g(\mathbf{\hat x})\]. We say
that we map from <italic>reference coordinates</italic> \[\mathbf{\hat x}\]
into <italic>world coordinates</italic> \[\mathbf x\]. Entities with the hat
(\[\hat{}\]) are in reference coordinates, entities without the hat are in
world coordines. The mapping \[g\] is affine linear and can thus be written as
<list><list-item dir="ltr">\[g(\mathbf{\hat x})=\mathrm B\mathbf{\hat
x}+\mathbf b\]</list-item></list>
The conversion of the vertex coordinates is simple:
<list><list-item dir="ltr">\[\mathbf x^i=\mathrm B\mathbf{\hat x}^i+\mathbf
b\]</list-item></list>
The tangential vectors and edge lengthes are a bit more complicated:
<list><list-item dir="ltr">\[\mathbf t^0=\frac{\mathbf x^1-\mathbf
x^0}{||\mathbf x^1-\mathbf x^0||}=\frac{\mathrm B(\mathbf{\hat
x}^1-\mathbf{\hat x}^0)}{||\mathrm B(\mathbf{\hat x}^1-\mathbf{\hat
x}^0)||}=\frac{\mathrm B\mathbf{\hat t}^0}{||\mathrm B\mathbf{\hat t}^0||}\],
\[\ell^0=||\mathbf x^1-\mathbf x^0||=||B(\mathbf{\hat x}^1-\mathbf{\hat
x}^0)||\]
</list-item><list-item dir="ltr">\[\mathbf t^1=\frac{\mathbf x^2-\mathbf
x^0}{||\mathbf x^2-\mathbf x^0||}=\frac{\mathrm B(\mathbf{\hat
x}^2-\mathbf{\hat x}^0)}{||\mathrm B(\mathbf{\hat x}^2-\mathbf{\hat
x}^0)||}=\frac{\mathrm B\mathbf{\hat t}^1}{||\mathrm B\mathbf{\hat t}^1||}\],
\[\ell^1=||\mathbf x^2-\mathbf x^0||=||B(\mathbf{\hat x}^2-\mathbf{\hat
x}^0)||\]
</list-item><list-item dir="ltr">\[\mathbf t^2=\frac{\mathbf x^2-\mathbf
x^1}{||\mathbf x^2-\mathbf x^1||}=\frac{\mathrm B(\mathbf{\hat
x}^2-\mathbf{\hat x}^1)}{||\mathrm B(\mathbf{\hat x}^2-\mathbf{\hat
x}^1)||}=\frac{\mathrm B\mathbf{\hat t}^2}{||\mathrm B\mathbf{\hat
t}^2||}\],\[\ell^2=||\mathbf x^2-\mathbf x^1||=||B(\mathbf{\hat
x}^2-\mathbf{\hat x}^1)||\]</list-item></list>
If we require that \[\hat\psi^i\] fullfills the same conditions in reference
coordinates as \[\psi^i\] fullfills in world coordinates, how what is the
transformation \[\psi^i(g(\mathbf{\hat x}))=L(\hat\psi^i(\mathbf{\hat x}))\]?
Let us assume that \[L\] is linear and independent of \[\mathbf x\] and
\[\mathbf{\hat x}\]:
<list><list-item dir="ltr">\[\mathbf y=L(\mathbf{\hat y})=\mathrm C\mathbf{\hat
y}+\mathbf c\]</list-item></list>
How do \[\mathrm C\] and \[\mathbf c\] relate to \[\mathrm B\] and \[\mathbf
b\]? We have the three vertex coordinates times two directions in each
coordinate to evaluate \[\psi^0\] and \[\hat\psi^0\], that should give us six
conditions with which we should be able to fix the six coefficients of
\[\mathrm C\] and \[\mathbf c\] (ideally, \[\mathbf c=0\]). OK, evaluating
just one basis function is probably not enough, since I already know what to
expect there. Instead, I probably have to evaluate a function \[\mathbf
y(\mathbf x)\] (\[\mathbf{\hat y}(\mathbf{\hat x})\]) to learn whats going on.
<list><list-item dir="ltr">Let \[\mathbf{\hat y}=\sum_iy^i\hat\psi^i\] and
\[\mathbf y=\sum_iy^i\psi^i\] with the same coeffitients
\[y^i\].</list-item></list>
Now we require \[\mathbf y(\mathbf x^i)=\mathrm C\mathbf{\hat y}(\mathbf{\hat
x}^i)+\mathbf c\]. We will not test this with cartesian components
</note-content></text>
<last-change-date>2009-06-13T13:45:31.8804240+02:00</last-change-date>
<last-metadata-change-date>2009-06-13T13:45:46.5230680+02:00</last-metadata-change-date>
<create-date>2009-06-13T07:02:50.7525010+02:00</create-date>
<cursor-position>31</cursor-position>
<width>582</width>
<height>489</height>
<x>425</x>
<y>89</y>
<tags>
<tag>system:notebook:Edge Basis and Transformation</tag>
</tags>
<open-on-startup>False</open-on-startup>
</note>
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--- End Message ---
--- Begin Message ---
Version: 0.5-5+rm
Dear submitter,
as the package tomboy-latex has just been removed from the Debian archive
unstable we hereby close the associated bug reports. We are sorry
that we couldn't deal with your issue properly.
For details on the removal, please see https://bugs.debian.org/910954
The version of this package that was in Debian prior to this removal
can still be found using http://snapshot.debian.org/.
This message was generated automatically; if you believe that there is
a problem with it please contact the archive administrators by mailing
[email protected].
Debian distribution maintenance software
pp.
Scott Kitterman (the ftpmaster behind the curtain)
--- End Message ---
