After applying the fix: nsw:/etc/init.d# /etc/init.d/proftpd restart [....] Stopping ftp server: proftpdstart-stop-daemon: --retry takes timeout, or schedule list of at least two items Try 'start-stop-daemon --help' for more information. start-stop-daemon: --retry takes timeout, or schedule list of at least two items Try 'start-stop-daemon --help' for more information. failed! [ ok ] Starting ftp server: proftpd.
nsw:/etc/init.d# dpkg -l | grep proftpd ii proftpd-basic 1.3.5~rc4-2 i386 Versatile, virtual-hosting FTP daemon - binaries ii proftpd-doc 1.3.5~rc4-2 all Versatile, virtual-hosting FTP daemon - documentation nsw:/etc/init.d# dpkg -l | grep dpkg ii dpkg 1.17.8 i386 Debian package management system The problem seems to be, that you need to specify full schedule to the --retry parameter, just "forever" is not enough. nsw:/etc/init.d# start-stop-daemon --help [---8<---] Retry <schedule> is <item>|/<item>/... where <item> is one of -<signal-num>|[-]<signal-name> send that signal <timeout> wait that many seconds forever repeat remainder forever or <schedule> may be just <timeout>, meaning <signal>/<timeout>/KILL/<timeout> [---8<---] Correct way would be something like --retry $SIGNAL/forever/5/KILL. That would first send signal, then repeat forever the sequence "wait 5 seconds, then send KILL". On my machine this seems to fix the original bug. Matus -- To UNSUBSCRIBE, email to [email protected] with a subject of "unsubscribe". Trouble? Contact [email protected]
