Hello all,
On Sun, 25 Apr 2021 17:33:28 +0000 Martin <deba...@debian.org> wrote:
On 2021-04-24 21:40, Steve McIntyre wrote:
There is no such thing as a "correct" formula, though. The old formula
was similarly causing lots of hassle for people installing on servers
who didn't want to waste hundreds of gigabytes on swap space.
There may not be a correct formula, but there are saner values than
others. AFAIK, "swap size = RAM size" is considered a sane default for
hibernation so e.g. I think that 16 GB swap in 500 GB disk space with 16
GB RAM is saner than 1 GB in most cases. On the other hand 1 GB swap in
8 GB disk space with 256 MB RAM is insane (yes I still have one such
machine).
What about something like "swap size = min(RAM size, disk space * R%)"
(with R to be defined) ?
Also I assume, that desktop PCs are more oftenly installed
relying on d-i defaults, while servers are typically installed
by experienced admins.
I agree and am afraid that the new swap size will bite many users who
want hibernation on desktop or laptop PCs and use guided partitioning.
Besides, I cannot even imagine anyone using guided partitioning on a server.
I'ld prefer the solution suggested in #780208, because it helps
in other cases, too.
Guided partitioning using LVM allows to reserve some free space in the
volume group, which can be used later to extend logical volumes.