Package: strace
Version: 4.5.14-2
Severity: normal
[EMAIL PROTECTED]:~$ strace -T sleep 2 2>&1 | grep nanosleep
nanosleep({2, 0}, NULL) = 0 <2.000024>
[EMAIL PROTECTED]:~$ strace -T -c sleep 2 2>&1 | grep nanosleep
nan 0.000000 0 1 nanosleep
Note that even though -T says the nanosleep() syscall takes about two full
seconds, -c still
says nanosleep took zero seconds.
Quoting the man page:
"
-T Show the time spent in system calls. This records the time difference
between the beginning and the end of each system call.
-c Count time, calls, and errors for each system call and report a summary on
program exit. On Linux, this attempts to show system time (CPU time spent
running in the kernel) independent of wall clock time.
"
Either a fix (preferred) or a clarification of the man page to explain *why* -c
ignores the -T
option on Linux would be nice.
Thanks! //Johan
-- System Information:
Debian Release: lenny/sid
APT prefers testing
APT policy: (990, 'testing')
Architecture: i386 (i686)
Kernel: Linux 2.6.21-2-686 (SMP w/2 CPU cores)
Locale: LANG=sv_SE.UTF-8, LC_CTYPE=sv_SE.UTF-8 (charmap=UTF-8)
Shell: /bin/sh linked to /bin/bash
Versions of packages strace depends on:
ii libc6 2.6.1-1+b1 GNU C Library: Shared libraries
strace recommends no packages.
-- no debconf information
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