Package: python2.5 Version: 2.5.4-1 Severity: normal Hi,
A bug has been posted against urlwatch: http://bugs.debian.org/cgi-bin/bugreport.cgi?bug=529740 It looks like there is a problem in urllib2. To reproduce it, you can run the following HTTP server [quote = http_server] import BaseHTTPServer class BrokenRequestHandler (BaseHTTPServer.BaseHTTPRequestHandler): def do_GET (self): self.wfile.write("") if __name__ == '__main__': handler_class=BrokenRequestHandler server_address = ('', 80) httpd = BaseHTTPServer.HTTPServer(server_address, handler_class) httpd.serve_forever() [/quote] With this script on the client side: [quote = client] req = urllib2.Request("http://192.168.2.2/index.html";,) try: urllib2.urlopen(req) except (urllib2.URLError), err: print err else: print "OK" [/quote] We get: [quote=error] Traceback (most recent call last): File "./bug_529740.py", line 8, in <module> urllib2.urlopen(req) File "/usr/lib/python2.5/urllib2.py", line 124, in urlopen return _opener.open(url, data) File "/usr/lib/python2.5/urllib2.py", line 381, in open response = self._open(req, data) File "/usr/lib/python2.5/urllib2.py", line 399, in _open '_open', req) File "/usr/lib/python2.5/urllib2.py", line 360, in _call_chain result = func(*args) File "/usr/lib/python2.5/urllib2.py", line 1107, in http_open return self.do_open(httplib.HTTPConnection, req) File "/usr/lib/python2.5/urllib2.py", line 1080, in do_open r = h.getresponse() File "/usr/lib/python2.5/httplib.py", line 928, in getresponse response.begin() File "/usr/lib/python2.5/httplib.py", line 385, in begin version, status, reason = self._read_status() File "/usr/lib/python2.5/httplib.py", line 349, in _read_status raise BadStatusLine(line) httplib.BadStatusLine [/quote] If we catch httplib.HTTPException: except (urllib2.URLError, httplib.HTTPException), err: then, it is fine. I think this error should be caught by urllib2.URLError. Any thoughts ? Regards, -- Franck Joncourt http://debian.org - http://smhteam.info/wiki/
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