On Sat, Jul 30, 2005 at 02:36:29PM -0700, Steve Langasek wrote:
>
> That doesn't make any sense; CPPFLAGS refers to flags for the C
> preprocessor, and one can clearly see three lines above that -fPIC is
> already being set in the PIC_CFLAGS variable where it belongs. The fix
> belongs elsewhere, wherever PIC_CFLAGS is failing to be included.
You're right, but I can't seem find the proper place to fix it.
What is being executed is it this:
.c.$(EXT_OBJ):
$(OCAMLC) -c -cc "$(CC)" -ccopt "$(CFLAGS) \
$(CPPFLAGS) $(CPPFLAGS_WIN32) \
$(CFLAGS_WIN32) $(CINCFLAGS) $(CFLAG_O)$@ " $<
And adding $(PIC_CFLAGS) fixes it, but really isn't what you
want.
An other part of the makefile says:
ifdef CREATE_LIB
CFLAGS := $(PIC_CFLAGS) $(CFLAGS)
CPPFLAGS := $(PIC_CPPFLAGS) $(CPPFLAGS)
Afaics, everywhere CPPFLAGS contains PIC_CPPFLAGS, CFLAGS
contains PIC_CFLAGS, so this isn't really making sense to me.
Kurt
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