<zitiere wer="Jonas Smedegaard">
Frank Wei�er wrote:
<zitiere wer="Maximilian Wilhelm">
RAID 5: (distributed space management) =====================================>> * at least 3 disc (normally equal size) * If all disc have the same size size(RAID) = (n - 1 / n) * disc size. * If one disc failes, replace it and be happy.
So you would have ~108GB useable space.
hmm, i always thought 3,75*36GB would be something like 135GB ;-)
Maybe it's just me, but how do you end up using 3,75? Are you perhaps setting up a RAID consisting of 4,75 disks?
(more likely you are quoting a different formula than the one you are using).
Can't see that: (4 - 1/4) = 3.75 , isn't it, or the () have to be set in another way!
You are right (in interpreting the above) - I need my glasses fixed.
Nevertheless I agree with the later post by Max: The right calculation (and the way I wrongly read the above) is this:
(n - 1) * [size of smallest disk]
- Jonas
P.S. Please do not cc me when addressing this list. A default rule of Debian mailinglists is to not cc unless explicitly asked for.
-- * Jonas Smedegaard - idealist og Internet-arkitekt * Tlf.: +45 40843136 Website: http://dr.jones.dk/
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