On 02/09/2004 Mike Mestnik wrote: > --- Jonas Meurer <[EMAIL PROTECTED]> wrote: > > so you mean that -d 62.75.128.98/31 is the same as two rules, one with > > -d 62.75.128.98 and one with -d 62.75.128.99? can you explain it, i > > don't understand ... > > It has todo with bit's, something called a bitmap. Here we go... > 1 and 0 is 1 > 0 and 0 is 0, and is recursive so > 0 and 1 is also 1 > > 1111:1110 and xxxx:xxxx is xxxx:xxx0
sorry, but what do you mean? the first 4 lines are clear, but what does this xxxx:xxxx mean? > 98d = 0110:0010 > 99d = 0110:0011 > 254d = 1111:1110 can you exemplify or somehow explain this? > 99d and 254d = 98d and 98d and 254d = 98d. > (98d and 254d) is also (99d and 254d). same for that. > So both 62.75.128.98 and 62.75.128.99 are in network > 62.75.128.98/255.255.255.254. This network could also be writen as > 62.75.128.98/31 saying that 31 out of 32 bits are set to 1 meaning that > the last one bit(s) are 0. ok, so 62.75.128.98/31 goes for all 62.75.128.* addresses? sorry i still don't feel like i understand your explanations ;( bye jonas
