The same syntax is accepted by the only other C++ compiler I have access
too: Sun's. I guess what I don't understand is why, if I create a
temporary by explicitly calling the copy constructor, that temporary is
treated as an rvalue.
So how do you want to proceed? If you're certain that you're correct
then I have no objection to you closing the bug report. Please do so
with my apologies for being a nuisance, as I'm certainly not sure that
I'm correct. Or if you prefer, I could post the question to comp.lang.c++.
thanks,
- jason
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