Dear Arie, when upgradeing uuagc for Debian, I’d like to avoid packaging uuagc-bootstrap, as it is just a copy of uuagc (right?). Given that uuagc already exists in Debian, can a new uuagc packages build using that? If so, how?
The documentation in Distribution.Simple.UUAGC seems to be outdated, but
I cannot pass uuagc to uuagcLibUserHook.
uuagc :: BuildInfo -> LocalBuildInfo -> PreProcessorSource
uuagcLibUserHook :: ([String] -> FilePath -> IO (ExitCode, [FilePath])) ->
UserHooksSource
Main hook, argument should be uuagc function
Thanks,
Joachim
--
Joachim "nomeata" Breitner
Debian Developer
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