On Sat, Jul 26, 2003 at 06:38:19PM +0000, Robert Millan wrote: > On Thu, Jul 24, 2003 at 12:14:57AM +0100, Roger Leigh wrote: > > [...] > > > > This seems rather complex! Why not just do something like: > > waittime = (long) (loadavg[0] / 16384) * 6 + 20; > > > > If you don't need SI_LOAD_SHIFT (Linux-specific??), it can probably be > > even simpler. > > Can I cast a double to long like that? What kind of truncating happens if > loadavg[0] is bigger than LONG_MAX? Does a division with 2^14 garantee it > will fit nicely?
So? Anyone has comments on this? -- Robert Millan "[..] but the delight and pride of Aule is in the deed of making, and in the thing made, and neither in possession nor in his own mastery; wherefore he gives and hoards not, and is free from care, passing ever on to some new work." -- J.R.R.T, Ainulindale (Silmarillion)
