On Sat, Jul 02, 2005 at 04:39:41PM +0200, Benedek Frank wrote:
> Maybe my method was wrong, here is how I did it:
>
> convert -quality 90 -scale '800x600>' *.JPG
>
[EMAIL PROTECTED] jpg $ ls
aaaa.jpg bbbb.jpg cccc.jpg dddd.jpg eeee.jpg
[EMAIL PROTECTED] jpg $ convert -quality 90 -scale '800x600>' *.jpg
[EMAIL PROTECTED] jpg $ ls
aaaa.jpg cccc.jpg eeee-0.jpg eeee-2.jpg eeee.jpg
bbbb.jpg dddd.jpg eeee-1.jpg eeee-3.jpg
This command works fine for me except as you can see it names the
files incorrectly
try this:
for i in *jpg; do echo "$i" ; convert -quality 90 -geometry x800 "$i" -geometry
x600 "$i" ; done
--
-----Angelina Carlton-----
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