Are you trying to cyclically permute the columns of a matrix? So for a 3x3 matrix of columns [A, B, C] you want [C, A, B]? Then you'd right multiply (X_new = X*M) by a matrix M = [0, 1, 0] [0, 0, 1] [1, 0, 0] (generalizing to higher dimensions is trivial).
And yes, this is not a particularly debian-laptop appropriate question. For math questions of this sort, I'd recommend browsing/posting at https://math.stackexchange.com/ On 05/08/2015 02:24 PM, giulianc51 wrote: > Il giorno Sat, 9 May 2015 01:21:44 +0530 > Arghya Das <[email protected]> ha scritto: > > Hi Arghya, > (sorry for my bad english) > > >> Does anyone know how to rotate a 2d matrix circularly for 'n' times in >> suppose C language...? It would be a lot of help if you could explain >> with code. > I don't understand your expression "rotate a 2d matrix circularly"; as > Jan-Rens explained you, you can build a matrix > M = | cos(theta) sin(theta)| > |-sin(theta) cos(theta)| > and a vector > X = | x | > | y | > (in linear algebra the vectors are column-wise); if you repeat the > multiplication X = M*X you have a series of vectors X, each rotating a > theta angle respect to the previous one; > > best regards, > giuliano > > > PS: if you want you can operate with row vectors using the > transposition X = X*transpose(M), but normally, as I said, the vectors > are disposed as column; > > -- To UNSUBSCRIBE, email to [email protected] with a subject of "unsubscribe". Trouble? Contact [email protected] Archive: https://lists.debian.org/[email protected]
