В Mon, 15 Sep 2008 21:28:54 +0200, Michael Biebl написа:
> I didn't know that
> foo: bar baz
> will result in bar/baz run in parallel. I thought there is some kind of
> guarantee that bar is processed first.
Consider this example which illustrates that it's not a safe
assumption to make always even with non-parallel make:
cat > makefile <<'EOF'
do-%: bar-% baz-%
@true
bar-%:
@echo I am first!
baz-foo:
@echo I should be second.
baz-frob:
@echo Something else.
EOF
$ make do-foo
I should be second.
I am first!
$ make -j2 do-foo
I should be second.
I am first!
$ make do-frob
Something else.
I am first!
When pattern rules come to the picture, and a pattern rule has
prerequisites which exist or are explicitly mentioned like here, they
always take precedence. You just have to be careful.
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