Hi, [Sorry for crossposting to debian-dpkg, but perhaps they could clarify this. Orig. post was: http://lists.debian.org/debian-mentors/2009/12/msg00075.html]
Erik Schanze <[email protected]>: > I added to my package "gif2png" the support of > DEB_BUILD_OPTIONS=parallel=n, as you can see in rules file. > > The output during build is: > ... > # Add here commands to compile the package. > > /usr/bin/make --jobserver-fds=3,4 -j > ... > > I don't know who changed $(MAKEFLAGS) from "-j3" to "--jobserver-fds=3,4 -j" > and > why the number "3" was not used after "-j". > > Could anybody please give an explanation? > Is there something broken or did I miss something? > As far as I understand, the substitution comes from "make" itself and it occurs in every sub-make during parallel build. So it seems the "make" call in build target of rules file is a sub-make call, right? But is it the intended behaviour, that the make call in "build" target will run with option "-j" without any number? Because this will end in a build run with unlimited jobs, or did I miss smth.? I expected that "make" call in "build" target will be executed with "-j <n>" with <n> from "DEB_BUILD_OPTIONS=parallel=<n>". If I use any other name than "MAKEFLAGS" for the variable, it works as expected. There is the key? A bit puzzled, Erik -- www.ErikSchanze.de ********************************************* Bitte keine HTML-E-Mails! No HTML mails, please! Limit: 100 kB * - Linux-Info-Tag in Dresden auch 2010 wieder * Info: http://www.linux-info-tag.de/ * -- To UNSUBSCRIBE, email to [email protected] with a subject of "unsubscribe". Trouble? Contact [email protected]
