On 19 Jan 2017, at 13:29, Jerome Kieffer <[email protected]> wrote: > > On Thu, 19 Jan 2017 11:50:18 +0000 > Ghislain Vaillant <[email protected]> wrote: > > >>>> Then there's the additional complication that x32 is a 32-bit version of >>>> amd64, so it shouldn't fail the test. Therefore, I would propose >>>> something like the following Debian-specific hack: >>>> >>>> host_cpu = subprocess.check_output(['dpkg-architecture', >>>> '-qDEB_HOST_ARCH_CPU']) >>>> if host_cpu != 'i386': >>>> # Do the assert > > Have you tried platfrom.machine ? it return either "i386" or "i686" > > It is cleaner but I don't know how it behaves with an "x32" kernel.
That doesn't help with i386 (or x32) chroots on an amd64 kernel. root@debian:/# uname -a Linux debian 4.9.0-1-amd64 #1 SMP Debian 4.9.2-2 (2017-01-12) x86_64 GNU/Linux root@debian:/# dpkg-architecture -qDEB_HOST_ARCH_CPU i386 root@debian:/# python3 -c "import platform; print(platform.machine())" x86_64 Regards, James
