On 28/12/15 14:11, [email protected] wrote: > It is not that simple. > Basically ( the Oracle guys should know more ) the OBP only initialises > a small block of memory so your image must fit into that space until it > has initialised enough memory management to use more space. > The clue is to cut the image down to the absolute minimum to get the > install started. Its a long time ago so my memory is a tad vague, I > seem to recall needing to use pivot root when I was working on Sparc32. > > Hope this helps.
According to the IEEE-1275 specification, 8M of memory is allocated at load-base (0x4000 default) by OBP, which is also what OpenBIOS does. Pretty much every bootloader I've looked at works by loading itself at load-base and then calling the OBP alloc routines based upon parsing the ELF header to reserve a chunk of memory for the kernel. These allocations are reflected in the memory and virtual-memory node memory properties which are subsequently parsed by the kernels to ensure that these mappings are maintained until the kernel takes over. ATB, Mark.
