On Thursday, December 17, 1998 12:48 PM, [EMAIL PROTECTED]
[SMTP:[EMAIL PROTECTED]] wrote:
> select a.CrossID, a.Name, a.LandScape, count(b.CrossID) as CountFld
> from ctabhed a left join ctabdat b on a.CrossID = b.CrossID
> group by a.CrossID, a.Name, a.LandScape
Looks likes it working anyway :) *yay*
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- RE: [DUG]: SQL Problem..... urgent answer required... Derricutt, Mark
