Re: [DUG]: drive path extraction

[abaddon]

On Sun, 2 Sep 2001 14:51:47 +0700, you wrote:


>of course on the 26th iteration it overwrites
>the old value also.   So the stuff in the 
>parentheses is correct, but vacuous.   No idea
>why i wrote that.   
>
cheers but what would i do just to get the drive letter of where the
application is executed so i can execute other programs on that same
path.


...
   Brendon Toogood

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