No. I tried:
if true and not false then
ShowMessage('Hi');
This works fine. So does
if (true) and not (false) then
ShowMessage('Hi');
However,
if true and not then
came up with a compile error.
What I suspect that Delphi does is interpret the thing from left to right.
So if A and B and C and D becomes: if (((A and B) and C) and D)
if A and not B and C and D becomes: if (((A and (not B)) and C) and D)
-----Original Message-----
From: Steve Peacocke [mailto:[EMAIL PROTECTED]
Sent: Monday, 10 March 2003 1:28 p.m.
To: Multiple recipients of list delphi
Subject: Re: [DUG]: coding
Alistair George said:
> Hi All.
> The following:
> if (DateSwitch) and not (RxCheckListBox6.Checked[2]) then
> CheckFileExist(VCLzip1.zipname); is not parsed correctly unless it is:
> if (DateSwitch) and (not RxCheckListBox6.Checked[2]) then
> CheckFileExist(VCLzip1.zipname);
Here's what Delphi is doing...
>if (DateSwitch) and not (Checked) then
If (true) and false(false) then
Delphi is not interpreting the line further than "not" as this equates to
false.
Where you have the brackets shown correctly the (not checked) is
interpreted as..
>if (DateSwitch) and (not Checked) then
If (true) and (true) then
Hope this helps (also secretely hopes this is a correct guess).
Steve
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