Title: Robert Martin
Brilliant will give it a go tomorrow.
All the file routines seem to be failing me !
Robert Martin
Software
development
manager
Chreos
www.chreos.co.nz
Ph +64 03 377-0495
be...@achieve.co.nz wrote:
Hi Rob,
I don't know if anyone answered this, but you can use the following to get the posted XML data and then load that into your XML processor.
$req = file_get_contents("php://input");
Regards,
Bevan
On Mon 11/05/09 11:21 AM , Robert martin r...@chreos.co.nz sent:
Hi all
I am wanting to send an XML file I have to a PHP script for
processing. I am wanting to use TidHttp and have the following code
snippet...
var
sResponse: String;
fsParams: TFileStream;
begin
fsParams := TFileStream.Create('.test.xml', fmOpenRead or
fmShareDenyWrite);
try
IdHTTP.Request.ContentType := 'text/xml';
sResponse :=
IdHTTP.Post('https://secure.dev.gateway.gov.uk/submission', fsParams);
ShowMessage(sResponse);
except
on E: Exception do
ShowMessage('Error encountered during POST: ' + E.Message);
end;
This was from a web site. Not mine !
But I wonder what should happen at the PHP end. When my scripts
processes usually things usually I go 'vardata = $_REQUEST[FieldName]
to get the value. Than my XML I should do something like
$xml = new SimpleXMLElement($vardata);
echo $xml->movie[0]->plot;
The question I have (which is Delphi related) is. My code doesn't
pass the XML file as a param (does it?) how should I do this or am I
misunderstanding.
Sorry if I have not been clear enough.
Thanks
Rob
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