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06 = 06 +07 = 0d +01 = 0e +73 = 81 +01 = 82 +00 = 82
and the other thing with keep the base byte means that at the end just make a (mysum and $ff to keep the first 8 bit).
Regards, Stefan Mueller
-----Original
Message-----
Hi all. I am pulling my hair out here at the moment.
I have this line of data :-
0df20a0a02450231384301000a
Its a hex data. Now the last 0A is the checksum. The document I have says that the checksum is made up of the SUM of BYTES for these values :-
0a 0a 02 45 02 31 38 43 01 00
and this line of data has a HEX checksum of 82 (thats 82 in HEX)
06 07 01 73 01 00
But I am stuffed if I can work it out. I thought I had it figured out, but NO !
Can someone enlighten me how to come to these values? I am SURE I am meant to know this, but its sure as hell not coming to me.
Cheers, Jeremy
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