Ah, but that is a different problem - the host no longer has any choice about which door to open, so he cannot influence the "value" of any doors.
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] On Behalf Of Nicholas DeLacey
Sent: Thursday,August,05,2004 4:42 p.m.
To: [EMAIL PROTECTED]
Subject: [DUG] RE: Delphi Digest, Vol 10, Issue 6
If that is correct then it follows that if there are three doors (2
goats and a car), but two people get to select a door (different doors)
and the other door is opened to reveal a goat, that then means that they
BOTH have a 2/3 chance of getting a car if they switch door choices.
Practical application will show that they both cannot get the car 2 out
of 3 times, as 4/3 is a bit more than 100%.
> From: Neven MacEwan <[EMAIL PROTECTED]>
>
>Guys
>
>The problem almost seems to be as much with the solution as it is with
>explaining it. Despite what Dieter says the solution is simple but
counter
>intuitive. When this problem was published in a column called 'Ask
Marilyn'
>(Marilyn von Savant) she was bombarded with Phd's and professors
telling
>her she was wrong - she was right.
>
>The simplist explaination I can come up with is:
>
>When you made your first choice you had a 2/3 chance of choosing a
>goat..agreed
>When you had the other goat revealed to you if you changed your choice
you
>would get the car if you had originally chosen a goat, a 2/3
possibility
>Therefore you ALWAYS change.
>
>Neven MacEwan (B.E. E&E)
>Ph. 09 621 0001 Mob. 0274 749062
3/4
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