Updated Package to reflect true nature of issue. ** Description changed:
Binary package hint: yelp I have a router that uses WPA2 security. My passphrase is a long string of random characters including characters like @#$&! . When I tried to use wpa_passphrase to convert my passphrase to HEX so I could manually enter that information into my interfaces file, wpa_passphrase errored out depending on which character it runs into (& or ! etc) because it treats it as a command option rather than part of the entire text string. The solution of course is to use a weak passphrase at the router that only uses standard alphanumeric characters but that is unacceptable for very secure locations. I was able to use a workaround at the following website: http://www.xs4all.nl/~rjoris/wpapsk.html That site allowed me to convert the passphrase to HEX successfully as it did not depend on the linux OS to perform the calculation. 1. I am on Ubuntu Studio 9.10 x64 2. I expected wpa_passphrase to handle non-alphanumeric characters. 3. Instead it errors out because it misinterprets the non-standard characters as command line options. ProblemType: Bug Architecture: amd64 Date: Thu Mar 25 13:38:04 2010 DistroRelease: Ubuntu 9.10 ExecutablePath: /usr/bin/yelp Package: yelp 2.28.0-0ubuntu2 ProcEnviron: - LANG=en_US.UTF-8 - SHELL=/bin/bash + LANG=en_US.UTF-8 + SHELL=/bin/bash ProcVersionSignature: Ubuntu 2.6.31-9.152-rt SourcePackage: yelp Uname: Linux 2.6.31-9-rt x86_64 ** Package changed: yelp (Ubuntu) => wpasupplicant (Ubuntu) -- wpa_passphrase errors out if non-standard characters are used https://bugs.launchpad.net/bugs/547110 You received this bug notification because you are a member of Ubuntu Desktop Bugs, which is subscribed to yelp in ubuntu. -- desktop-bugs mailing list [email protected] https://lists.ubuntu.com/mailman/listinfo/desktop-bugs
