See https://developer.mozilla.org/en-US/docs/WebAPI/Web_Activities
I think you want "view".
The docs say:
type: "url"
url: {
required: true,
regexp: /^https?:.{1,16384}$/
}
Which means something lihe this:
new MozActivity({
"name":"view",
"data":
{
"type":"url",
"url":"http://mozilla.org";
}
});
On Apr 10, 2013, at 7:02 AM, Flaki wrote:
> Hello everyone!
>
> I'm building an app that tries to interact with the FourSquare OAuth service
> to authenticate. Unfortunately, FourSquare requires for the app authorization
> the user to be redirected to foursquare's own webpage (needs to be opened in
> a browser), where the user authorizes the app, then it redirects the browser
> to a pre-set url.
>
> Launching the authorization works like a charm, the "view" webactivity opens
> up the browser and authentication works as it should. However reopening the
> app is a hassle (the user must be presented a page after redirect, that
> instructs him to reopen the app and refresh/sync to receive his auth key).
>
> Browsing the WebActivity docs (which are quite scarce, at most)
A spiteful and malicious falsehood! Ok we are working on it. ;) Follow the
status here:
https://developer.mozilla.org/en-US/docs/WebAPI/Doc_status
> I found out there is an "open" action, could probably this be used to launch
> the app from the browser? I'm thinking something not at all unlike android's
> intents... Unfortunately I didn't find any pointers (or any documentation)
> for the action.
>
> Thanks in advance!
> Flaki
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