Am 24.10.2011 um 14:18 schrieb Hans Hagen:
> On 21-10-2011 07:07, Wolfgang Schuster wrote:
>> Hi Hans,
>>
>> I try to set and access a reference in the example below but both
>> \in and \at result in a fatal error. What’s missing in my code,
>> I looked in the float and math code but I can’t find a solution.
>
> you need to set a resolver for the internal reference as it can come from
> anywhere
>
> references.resolvers.test = references.resolvers.section -- take from list
>
> but anyhow, I made that the fallback resolver now so your problem should go
> away
Thanks, the error message is now gone but I don’t get a number from the \in
reference unless I add
\startluacode
structures.references.filters.test = { default =
structures.references.filters.generic.number }
\stopluacode
to my code. Can the reference code take care of this itself or do I really need
the line?
Wolfgang
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