On Sun, Sep 5, 2021 at 2:22 AM Reinhard Kotucha <[email protected]>
wrote:
> Hi,
> on a 64 bit Windows machine os.uname() erroneously returns
>
> machine i686
>
> On the same machine I get under Linux
>
> machine x86_64
>
> with both, x86_64-linux and i386-linux binaries. Thus I assume that
> the keyword 'machine' refers to the hardware, not to how the binaries
> were compiled (32 vs. 64 bit).
>
> The complete output of
>
> for k,v in pairs(os.uname()) do
> print(k,v)
> end
>
> is
>
> release build 9200
> nodename R804
> version 6.02
> machine i686
> sysname Windows 8
>
>
#ifdef _WIN32
# define _UTSNAME_LENGTH 65
/* Structure describing the system and machine. */
struct utsname {
char sysname[_UTSNAME_LENGTH];
char nodename[_UTSNAME_LENGTH];
char release[_UTSNAME_LENGTH];
char version[_UTSNAME_LENGTH];
char machine[_UTSNAME_LENGTH];
};
/*
* Get name and information about current kernel.
*/
static int uname(struct utsname *uts)
:
case WinNT:
sprintf(uts->machine, "i%d86", sysinfo.wProcessorLevel);
break;
I guess that wProcessorLevel gives 6 in your case.
--
luigi
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