The thing I don't understand is why this special operator even exists, since I have never seen the "\" operator before. And so the question is what 11/3 should really return. I don't know what it returns in VisualBasic (since SB should resemble VB), but I would rather like to have it the C way.
There is also an open issue on this, it would love to get some more attention I guess ;-). http://qa.openoffice.org/issues/show_bug.cgi?id=51219 2005/12/14, Laurent Godard <[EMAIL PROTECTED]>: > Hi Felix, > > > How do I perform an integer division (e.g. 11 / 3 = 4) in OpenOffice Basic? > > try this > 11 \ 3 = 3 > or fix(11/3) > > the rounding depends of what you need > for me 11/3 is rounded to 3 > > Laurent -- Best Regards Christian Junker --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
