Am 08.08.2011 16:45, schrieb Johnny Rosenberg:
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...
</snip>
> 
> I guess I'll stick with my own Frac function then, since it's more
> straight forward and easier to understand. And shorter…
> 
> Function Frac(Value As Double) As Double
>      Frac=Value-Fix(Value)
> End Function
> 

Yes, of course. And I think also with less overhead (not using an UNO
Object)

;-)
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