Hi all,Can anyone explain the contract for apr_brigade split? I have read and reread the doxygen description, and it makes no sense to me.
apr_bucket_brigade* a = apr_brigade_split(apr_bucket_brigade *b,
apr_bucket *e)
As I understand it, brigade b, is split in two. After the split, some of
the brigade is in a, and some of the brigade is in b.
Is the brigade in a the leftmost part of the brigade, or the rightmost part of the brigade?
Which brigade will bucket e fall into, a or b? Regards, Graham --
smime.p7s
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