C++ generate nullable types for optional fields int the schema
---------------------------------------------------------------
Key: AVRO-840
URL: https://issues.apache.org/jira/browse/AVRO-840
Project: Avro
Issue Type: Improvement
Components: c++
Reporter: Ramana Suvarapu
Priority: Critical
To represent optional fields, we use unions in our schema. See the example
below.
{
"type" : "record",
"name" : "Contact",
"fields" : [
{"name" : "FirstName","type" : ["string" ]},
{"name" : "MiddleName","type" : [null, "string" ]},
{"name" : "LastName", "type" : ["string" ]},
{"name" : "PhoneNum","type" : [null, "string" ]},
{"name" : "Id","type" : [null, "long" ]}
]
}
In this schema PhoneNum, MiddleName and Id fields are declared as unions as
they are optional fields. For this schema, Avrogencpp generates Contact
structure and 3 separate union structures for each of the optional fields in
the schema.
struct Contact
{
String FirstName;
String LastName;
Union_0 MiddleName;
Union_1 PhoneNum;
Union_3 Id;
}
Instead is it possible to create a new template based NullableType to represent
optional fields. Basically if the schema has union with 2 fields and first
field is null, it should generate Nullable type.
For the above scheme, it should generate something like this.
struct Contact
{
String FirstName;
String LastName;
Nullable<string> MiddleName;
Nullable<string> PhoneNum;
Nullable< long > Id;
}
This will reduce the number of generated unions in generated code and improve
the readability and usability of the code.
Let me know if it's feasible to implement this.
Thanks,
Ramana
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