Congrats everyone ! On Thu, May 2, 2019 at 9:14 AM Robert Bradshaw <rober...@google.com> wrote:
> Congratulation, and thanks for all the great contributions each one of you > has made to Beam! > > On Thu, May 2, 2019 at 5:51 AM Ruoyun Huang <ruo...@google.com> wrote: > >> Congratulations everyone! Well deserved! >> >> On Wed, May 1, 2019 at 8:38 PM Kenneth Knowles <k...@google.com> wrote: >> >>> Congrats! All well deserved! >>> >>> Kenn >>> >>> On Wed, May 1, 2019 at 8:09 PM Reza Rokni <r...@google.com> wrote: >>> >>>> Congratulations! >>>> >>>> On Thu, 2 May 2019 at 10:53, Connell O'Callaghan <conne...@google.com> >>>> wrote: >>>> >>>>> Well done - congratulations to you all!!! Rose thank you for sharing >>>>> this news!!! >>>>> >>>>> On Wed, May 1, 2019 at 19:45 Rose Nguyen <rtngu...@google.com> wrote: >>>>> >>>>>> Matthias Baetens, Lukazs Gajowy, Suneel Marthi, Maximilian Michels, >>>>>> Alex Van Boxel, and Thomas Weise: >>>>>> >>>>>> Thank you for your exceptional contributions to Apache Beam.👏 I'm >>>>>> looking forward to seeing this project grow and for more folks to >>>>>> contribute and be recognized! Everyone can read more about this award on >>>>>> the Google Open Source blog: >>>>>> https://opensource.googleblog.com/2019/04/google-open-source-peer-bonus-winners.html >>>>>> >>>>>> Cheers, >>>>>> -- >>>>>> Rose Thị Nguyễn >>>>>> >>>>> >>>> >>>> -- >>>> >>>> This email may be confidential and privileged. If you received this >>>> communication by mistake, please don't forward it to anyone else, please >>>> erase all copies and attachments, and please let me know that it has gone >>>> to the wrong person. >>>> >>>> The above terms reflect a potential business arrangement, are provided >>>> solely as a basis for further discussion, and are not intended to be and do >>>> not constitute a legally binding obligation. No legally binding obligations >>>> will be created, implied, or inferred until an agreement in final form is >>>> executed in writing by all parties involved. >>>> >>> >> >> -- >> ================ >> Ruoyun Huang >> >>
