chenBright commented on code in PR #2942:
URL: https://github.com/apache/brpc/pull/2942#discussion_r2036420248
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src/butil/iobuf.cpp:
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@@ -1371,6 +1412,35 @@ IOBuf::Area IOBuf::reserve(size_t count) {
return result;
}
+IOBuf::Area IOBuf::reserve_aligned(size_t n, size_t alignment) {
+ bool is_power_two = alignment > 0 && (alignment & (alignment - 1));
+ if (is_power_two != 0) {
+ LOG(ERROR) << "Invalid alignment, must power of two";
+ return INVALID_AREA;
+ }
+ size_t count = (n + alignment - 1) & ~(alignment - 1);
+ IOBuf::Area result = INVALID_AREA;
+ size_t total_nc = 0;
+ while (total_nc < count) { // excluded count == 0
+ IOBuf::Block* b = iobuf::share_tls_aligned_block(alignment);
Review Comment:
前面不符合alignment的，每次都会遍历，是不是没有必要？
可以将上次的遍历结果传进去作为hint吗？
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