Caican Cai created CALCITE-6203:
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             Summary: Avg operator test in SparkAdapterTest
                 Key: CALCITE-6203
                 URL: https://issues.apache.org/jira/browse/CALCITE-6203
             Project: Calcite
          Issue Type: Test
          Components: spark
    Affects Versions: 1.36.0
            Reporter: Caican Cai
             Fix For: 1.37.0


I test the avg operator in SparkAdapterTest

@Test void testGroupBy() {
    final String sql = "select sum(x) as SUM_X, min(y) as MIN_Y, max(y) as 
MAX_Y, avg(x) as AVG_X,"
        + "count(*) as CNT_Y, count(distinct y) as CNT_DIST_Y\n"
        + "from " + VALUES2 + "\n"
        + "group by x";

    final String plan = "PLAN="
        + "EnumerableCalc(expr#0..5=[\{inputs}], expr#6=[CAST($t1):INTEGER NOT 
NULL], expr#7=[CAST($t2):CHAR(1) NOT NULL], expr#8=[CAST($t3):CHAR(1) NOT 
NULL], expr#9=[CAST($t4):BIGINT NOT NULL], SUM_X=[$t6], MIN_Y=[$t7], 
MAX_Y=[$t8], AVG_X=[$t0], CNT_Y=[$t9], CNT_DIST_Y=[$t5])\n"
        + "  EnumerableAggregate(group=[\{0}], SUM_X=[MIN($2) FILTER $7], 
MIN_Y=[MIN($3) FILTER $7], MAX_Y=[MIN($4) FILTER $7], CNT_Y=[MIN($5) FILTER 
$7], CNT_DIST_Y=[COUNT($1) FILTER $6])\n"
        + "    EnumerableCalc(expr#0..6=[\{inputs}], expr#7=[0], expr#8=[=($t6, 
$t7)], expr#9=[1], expr#10=[=($t6, $t9)], proj#0..5=[\{exprs}], $g_0=[$t8], 
$g_1=[$t10])\n"
        + "      EnumerableAggregate(group=[\{0, 1}], groups=[[\{0, 1}, \{0}]], 
SUM_X=[$SUM0($0)], MIN_Y=[MIN($1)], MAX_Y=[MAX($1)], CNT_Y=[COUNT()], 
$g=[GROUPING($0, $1)])\n"
        + "        EnumerableValues(tuples=[[\{ 1, 'a' }, \{ 2, 'b' }, \{ 1, 
'b' }, \{ 2, 'c' }, \{ 2, 'c' }]])\n";

    final String[] expectedResult = {
        "SUM_X=2; MIN_Y=a; MAX_Y=b; AVG_X=1; CNT_Y=2; CNT_DIST_Y=2",
        "SUM_X=6; MIN_Y=b; MAX_Y=c; AVG_X=2; CNT_Y=3; CNT_DIST_Y=2"
    };

    sql(sql).returnsUnordered(expectedResult)
        .explainContains(plan);
  }

 

It can be found that there is no corresponding avg operator in 
EnumerableAggregate and EnumerableCalc. Why is this? Spark sql will split the 
avg operator into sum/count form. I don’t know if this is a bug.

 

 



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