> -----Original Message-----
> From: Vadim Gritsenko [mailto:[EMAIL PROTECTED]
> Sent: Dienstag, 31. Mai 2005 15:30
> To: [email protected]
> Subject: Re: [RFE] Some enhancements to XSP
> > Instead of "?" one could also use another character provided it is
> > sufficiently
> > unlikely that the sequence curly-char appears in XSP-embedded content or
> > where
> > XSP can be embedded (XSL). The special character should not be valid at the
> > beginning of an expression at least for CSS, HTML, Java, Javascript, Perl,
> > and XSLT. That excludes
> >
> > + " * % & ` @ ' ^ ~ ! [ $ - . ( /
> >
> > but leaves as sensible alternatives
> >
> > {#expr}
> > {=expr}
> > {:expr}
> > {?expr}
> >
> > Whatever special character we agree on, it should be always the same in all
> > contexts and always enabled.
> >
> > Any preferrences which character to use?
>
> Yes. Given that (a) XSLT already has '{foo}' syntax, and uses '{{foo}}' for
> escaping; and given that the only other XSP implementation (AxKit) uses same
> syntax as in XSLT, I'm for using that same syntax too.
I think it is a bad idea to use exactly the same syntax as for XSLT because it
makes really awkward to use XSP attribute interpolation inside logicsheets.
You end up wasting your time figuring out which curly mountain is needed to
get the expression to be interpreted by the right engine.
It should be easy for both humans and the XSP processor to distinguish between
XSP and XSLT expressions.
I don't know AxKit in detail but I assume that them using "{foo}" syntax means
that they are not using XSLT-based logicsheets. Anyway, we can still claim to
use a common standard by defining:
interpolated-expr ::= '{' language-expr '}'
language-expr ::= perl-expr | '?' java-expr | '?' javascript-expr | '?'
python-expr
> As for backward compatibility, is is already solved by:
>
> <xsp:page attribute-value-interpolation="no">
But the default value should be attribute-value-interpolation="yes", provided
we can agree on a syntax which is highly unlikely to be used in existing XSPs.
Cheers, Alfred.
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