On 18.07.2007 12:16, Felix Knecht wrote:

         if (getLogger().isDebugEnabled()) {
-            getLogger().debug("Source " + super.source +
+            getLogger().error("Source " + super.source +
                               " resolved to " + this.inputSource.getURI());
Sorry, but I do not understand why this needs to be logged to error?

Independent from the answer it will not log anyway if the log level is not at least debug because of isDebugEnabled().

Joerg

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