thebti created HTTPCLIENT-1243:
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             Summary: Processing Multipart Response entity - BUG
                 Key: HTTPCLIENT-1243
                 URL: https://issues.apache.org/jira/browse/HTTPCLIENT-1243
             Project: HttpComponents HttpClient
          Issue Type: Bug
          Components: HttpClient, HttpMime
    Affects Versions: 4.2.1
         Environment: HttpClient 4.2.1, 
            Reporter: thebti


Hi, I got an arrayOutOfBound exception (multipart getCount() = 1) on the line 
11 of the folowing code. The first InputStream inP1 was troncated (not 
complete).

import javax.activation.DataSource;
import javax.mail.BodyPart;
import javax.mail.internet.MimeMultipart;

1 HttpClient httpclient = new DefaultHttpClient();
2 HttpResponse response = null;
3 try {
4     HttpPost httppost = new 
HttpPost("http://localhost:8080/HttpClientTest/servlet/MutipartExample";);
5     response = client.execute(post);
6     InputStream responseAsStream = response.getEntity().getContent();
7     DataSource ds = new DataSourceForHttpResponseMultipart(responseAsStream);
8     MimeMultipart mp = new MimeMultipart(ds);
9     BodyPart bodyPart1 = mp.getBodyPart(0);
10   InputStream inP1 = bodyPart1.getInputStream();
11   BodyPart bodyPart2 = mp.getBodyPart(1);
12   InputStream inP2 = bodyPart2.getInputStream();
}

with DataSourceForHttpResponseMultipart implementation
public class DataSourceForHttpResponseMultipart implements DataSource {
        InputStream in;
        public DataSourceForHttpResponseMultipart(InputStream in) {
                this.in = in;
        }
        public String getContentType() {
                return "multipart/mixed; boundary=Strs";
        }
        public InputStream getInputStream() throws IOException {
                return in;
        }
        public String getName() {
                return null;
        }
        public OutputStream getOutputStream() throws IOException {
                return null;
        }
}

I found a solution to patch this bug, by changing line 7, by this :
7   DataSource ds = new DataSourceForHttpResponseMultipart(new 
ByteArrayInputStream(IOUtils.toByteArray(responseAsStream)));

Thanks.
Thebti


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