Choi JaeHwan created HIVE-18268: ----------------------------------- Summary: Hive Prepared Statement when split with double quoted in query fails Key: HIVE-18268 URL: https://issues.apache.org/jira/browse/HIVE-18268 Project: Hive Issue Type: Bug Components: JDBC Affects Versions: 2.3.2 Reporter: Choi JaeHwan Assignee: Choi JaeHwan
HIVE-13625, Change sql statement split when odd number of escape characters, and add parameter counter validation, above {code:java} // prev code StringBuilder newSql = new StringBuilder(parts.get(0)); for(int i=1;i<parts.size();i++){ if(!parameters.containsKey(i)){ throw new SQLException("Parameter #"+i+" is unset"); } newSql.append(parameters.get(i)); newSql.append(parts.get(i)); } // change from HIVE-13625 int paramLoc = 1; while (getCharIndexFromSqlByParamLocation(sql, '?', paramLoc) > 0) { // check the user has set the needs parameters if (parameters.containsKey(paramLoc)) { int tt = getCharIndexFromSqlByParamLocation(newSql.toString(), '?', 1); newSql.deleteCharAt(tt); newSql.insert(tt, parameters.get(paramLoc)); } paramLoc++; } {code} If the number of split SQL and the number of parameters are not matched, an SQLException is thrown Currently, when splitting SQL, there is no processing for double quoted, and when the token ('?' ) is between double quote, SQL is split. i think when the token between double quoted is literal, it is correct to not split. for example, above the query; {code:java} // Some comments here 1: String query = " select 1 from x where qa="?" " 2: String query = " SELECT 1 FROM `x` WHERE (trecord LIKE "ALA[d_?]%") {code} ? is literal, then query do not split. -- This message was sent by Atlassian JIRA (v6.4.14#64029)