Choi JaeHwan created HIVE-18268:
-----------------------------------
Summary: Hive Prepared Statement when split with double quoted in
query fails
Key: HIVE-18268
URL: https://issues.apache.org/jira/browse/HIVE-18268
Project: Hive
Issue Type: Bug
Components: JDBC
Affects Versions: 2.3.2
Reporter: Choi JaeHwan
Assignee: Choi JaeHwan
HIVE-13625, Change sql statement split when odd number of escape characters,
and add parameter counter validation, above
{code:java}
// prev code
StringBuilder newSql = new StringBuilder(parts.get(0));
for(int i=1;i<parts.size();i++){
if(!parameters.containsKey(i)){
throw new SQLException("Parameter #"+i+" is unset");
}
newSql.append(parameters.get(i));
newSql.append(parts.get(i));
}
// change from HIVE-13625
int paramLoc = 1;
while (getCharIndexFromSqlByParamLocation(sql, '?', paramLoc) > 0) {
// check the user has set the needs parameters
if (parameters.containsKey(paramLoc)) {
int tt = getCharIndexFromSqlByParamLocation(newSql.toString(), '?', 1);
newSql.deleteCharAt(tt);
newSql.insert(tt, parameters.get(paramLoc));
}
paramLoc++;
}
{code}
If the number of split SQL and the number of parameters are not matched, an
SQLException is thrown
Currently, when splitting SQL, there is no processing for double quoted, and
when the token ('?' ) is between double quote, SQL is split.
i think when the token between double quoted is literal, it is correct to not
split.
for example, above the query;
{code:java}
// Some comments here
1: String query = " select 1 from x where qa="?" "
2: String query = " SELECT 1 FROM `x` WHERE (trecord LIKE "ALA[d_?]%")
{code}
? is literal, then query do not split.
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