Francis Daly <[EMAIL PROTECTED]> writes:
> 8 is a magic number. How about
>
> printf("Pointer size: %d bits\n", CHAR_BIT*sizeof(void*)); ?
>
> to allow for any machine which has some other number of bits in a
> (C-)byte.
So what is more likely?
a) 8 * sizeof(void *) breaks because there aren't 8 bits in a byte
b) CHAR_BIT * sizeof(void *) breaks because while there may be 8 bits
in a byte a char is two bytes
c) CHAR_BIT * sizeof(void *) breaks because CHAR_BIT isn't defined or
<limits.h> doesn't exist
:)
(I don't mean to say anything bad about your suggestion.)
--
Jeff Trawick | [EMAIL PROTECTED] | PGP public key at web site:
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Born in Roswell... married an alien...
