My Base64 decoder did not decode it :-(
Anyway, I always get 'user /...: authentication failure for "/path/":
Password Mismatch', although my password file looks correct:
/C=BE/ST=Belgium/L=Brussels/O=Approach Belgium/OU=Apache test
certificate/CN=127.0.0.1:xxj31ZMTZzkVA
Does 2.2.6 it use another hash algorithm by default or so ?
For info, I use
SSLVerifyClient require
<Location "/">
SSLRequireSSL
SSLOptions +FakeBasicAuth
Authname "NSA protected site for countries"
AuthType Basic
AuthUserFile conf/users.auth
Require valid-user
</Location>
Henrik Nordstrom wrote:
On ons, 2007-09-26 at 18:06 +0200, Nick Gearls wrote:
In the debug log, I can find:
Faking HTTP Basic Auth header: "Authorization: Basic
L0M9QkUvU1Q9QmVsZ2l1bS9MPUJydXNzZWxzL089QXBwcm9hY2ggQmVsZ2l1bS9PVT1BcGFjaGUgdGVzdCBjZXJ0aWZpY2F0ZS9DTj0xMjcuMC4wLjE6cGFzc3dvcmQ="
What is this header contents ? Isn't it supposed to be base64 ? I cannot
decode it.
It's base64. Decoding it gives
"/C=BE/ST=Belgium/L=Brussels/O=Approach Belgium/OU=Apache test
certificate/CN=127.0.0.1:password"
Regards
Henrik
