I have a case that I know falls under Don't Do That (DDT), but it got me wondering.
Background: We have created a custom data type that extends AdhocDatatype and provides a data type for an enum. The parse() and unparse() methods work as expected. I have a test case that managed to create 2 instances of the datatype (this is the DDT part). I will be spending this morning figuring out why we do this and what the proper solution is. But it got me thinking. The isomorphic test fails on the enum data type based literals. Looking at the code, in BaseDatatype.java, it perfors Object.equals( datatype1, datatype2 ) in the various equality checks. Question: Since the two datatype instances return the same enum, and the lexical form of the two is the same, and there is no language specified, should they not be considered equal? Should the two graphs not be considered isomorphic? If not can someone explain why? Claude -- I like: Like Like - The likeliest place on the web <http://like-like.xenei.com> LinkedIn: http://www.linkedin.com/in/claudewarren
