(query.Whatever / query.RecordCount) * 100

???


Duncan Cumming
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http://www.alienationdesign.co.uk
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                    "Damian Watson"                                                    
                                     
                    <[EMAIL PROTECTED]        To:     <[EMAIL PROTECTED]>              
                       
                    ign.co.uk>                    cc:                                  
                                     
                                                  Subject:     Re: [ cf-dev ] 
percentages of values in recordset            
                    11/06/2003 15:36                                                   
                                     
                    Please respond to dev                                              
                                     
                                                                                       
                                     
                                                                                       
                                     



Thanks Rich, don't think I explained myself very well though. What I'm
trying to do is:

SELECT myValue, COUNT(myValue) AS Whatever
FROM myTable
Where myValue=1 (and then on up to 5)

Then output the count as a percentage of the whole recordcount.

I realise I could loop it from 1 to 5 but myValue is already being looped
and I'm going to end up with a silly amount of queries generated

Cheers
d

----- Original Message -----
From: "Rich Wild" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, June 11, 2003 3:12 PM
Subject: RE: [ cf-dev ] percentages of values in recordset


> SELECT myValue, COUNT(myValue)
> FROM myTable
> GROUP BY myValue
>
> > -----Original Message-----
> > From: Damian Watson [mailto:[EMAIL PROTECTED]
> > Sent: 11 June 2003 15:21
> > To: [EMAIL PROTECTED]
> > Subject: [ cf-dev ] percentages of values in recordset
> >
> >
> > Hi,
> >
> > Pretty dumbass question but I'm working on a poll where for
> > instance I have
> > a column with 5 possible values (1 to 5).
> >
> > Say there are 50 records. How do I get the number of records
> > for each value
> > without doing 5 queries?
> >
> > Cheers
> > d
> >
> >
> >
> > --
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>
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